X^2-5=95x=10

Solution for X^2-5=95x=10 equation:

X^2-5=95X=10

We move all terms to the left:

X^2-5-(95X)=0

a = 1; b = -95; c = -5;
Δ = b2-4ac
Δ = -952-4·1·(-5)
Δ = 9045
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9045}=\sqrt{9*1005}=\sqrt{9}*\sqrt{1005}=3\sqrt{1005}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-3\sqrt{1005}}{2*1}=\frac{95-3\sqrt{1005}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+3\sqrt{1005}}{2*1}=\frac{95+3\sqrt{1005}}{2}
$